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9x+180=x^2
We move all terms to the left:
9x+180-(x^2)=0
determiningTheFunctionDomain -x^2+9x+180=0
We add all the numbers together, and all the variables
-1x^2+9x+180=0
a = -1; b = 9; c = +180;
Δ = b2-4ac
Δ = 92-4·(-1)·180
Δ = 801
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{801}=\sqrt{9*89}=\sqrt{9}*\sqrt{89}=3\sqrt{89}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-3\sqrt{89}}{2*-1}=\frac{-9-3\sqrt{89}}{-2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+3\sqrt{89}}{2*-1}=\frac{-9+3\sqrt{89}}{-2} $
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